Find the zeros of the quadratic polynomial t square - 25
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Answered by
20
f(x)= t^2 - 25
=t^2-5^2
Of the form a^2-b^2=(a+b)(a-b)
=(t+5)(t-5)
f(x)=0
=>(t-5)(t+5)=0
=>t= 5 or, t= -5
=t^2-5^2
Of the form a^2-b^2=(a+b)(a-b)
=(t+5)(t-5)
f(x)=0
=>(t-5)(t+5)=0
=>t= 5 or, t= -5
Answered by
6
Answer:
Let p(t)=t^2-25
=t^2- 5^2
Using identity:- a^2-b^2=(a+b)(a-b)
=(t+5)(t-5)
Therefore, t=5 and t=-5 are zeroes of p(t).
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