Question

find the zeros of the quadratic polynomial
$4 {x}^{2} - 3x - 1$
​

Answer 1

Heya❤

$4x {}^{2} - 3x - 1 \\ 4x {}^{2} - 4x + x - 1 \\ 4x(x - 1) + 1(x - 1) \\ (4x + 1)(x - 1)$

Now,

4x+1=0

4x= -1

☆ x= $\frac {-1}{4}$☆

x-1=0

☆x=1☆

Hope it helps you

✌✌✌

Answer 2

Hello ☺

$4 {x}^{2} - 3x - 1 = 0 \\ \\ 4 {x}^{2} - 4x + x - 1 = 0 \\ \\ 4x(x - 1) + 1(x - 1) = 0 \\ \\ (4x + 1)(x - 1) = 0 \\ \\ x = \frac{ - 1}{4} \: or \: x = 1$

Zeros of the quadratic equation are -1/4 and 1.

HOPE IT HELPS YOU ❤