Question

Find the zeros of the quadratic polynomial x?+7x+10, and verify relationship
between zeros and coefficients.
hose sum and product of its zeros are 1,1.​

Answer 1

Answer:

x²+7x+10=0

=>x²+5x+2x+10=0

=>x(x+5)+2(x+5)=0

=>(x+2)(x+5)=0

x=-2 and x=-5

Verification:-

Here, a=1, b=7, c=10

•Sum of zeroes = -b/a

= -7/1

=7

•Product of zeroes = c/a

= 10/1

= 10

And that's all your answer

Answer 2

Step-by-step explanation:

p(x)= x^2+7x+10

= x^2+5x+2x+10 ( middle term split )

=x(x+5)+2(x+5)

=(x+2) (x+5)

alpha (a)=x+2=0

=x= -2

bita(b)=x+5=0

=x= -5

verification between zeros and the coefficient:-

(i) a+b =-b/a

=-2+-5=-7/1

=-2-5=-7

=-7 = -7

(ii) ab =c/a

=-2×-5 =10/1

=10=10

verified -