Question

find the zeros of the quadratic polynomial X square + 7 x + 10 and 5 and verify the relationship between the zeros and the coefficients

Answer 1

Hey friend ✋! here is your answer

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◆To find zeros of x^2+7x+10

✅By factorization method

✔️x^2+5x+2x+10

✔️Taking common

✅x(x+5)+2(x+5)

✔️(x+2)(x+5)=0

✅x+2=0 & x+5=0

✔️x=-2 & x=-5

alpha=-2 & beta=-5

⭕️⭕️ Verification

✅a=1. b=7. & c=5
alpha + beta=-b/a

◆alpha + beta=-2+(-5)=-7

◆-b/a=-7/1=-7

✅✅alpha × beta=c/a

✔️alpha ×beta=(-2)×(-5)=10

✅✅C/a =10/1=10

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⭐️Hope it helps you ⭐️

#Rohan ( Maths aryabhatt)♥️

Answer 2

Answer:

x²+7x+10=0

x²+2x+5x+10=0

x(x+2)+5(x+2)=0

(x+2)(x+5) = 0

x+2 = 0 ; x = -2

x+5 = 0 ; x = -5

Relationship between the zeroes and coefficients :-

Sum of zeroes = -2+(-5) = -2-5

= -7/1 = -x coefficient /x² coefficient

Product of zeroes = (-2)(-5)

= 10/1 = constant/x² coefficient

Step-by-step explanation: