Find the zeros of the quadratic polynomial x2-2x-8
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Given Polynomial ,
x²-2x-8
By Middle Splitting Method
x²-2x-8 = x²-4x+2x-8 = x(x-4)+2(x-4)
= (x-4)(x+2)
Either , x-4 = 0
=> x = 4 .
OR , x+2 = 0
=> x = -2
So , Zeroes are 4 and -2 ....
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