Question

Find the zeros of the quadratic polynomial:
x2−5x+6.

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Answer 1

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${x}^{2} - 5x + 6 = 0$

$- B \frac{± \sqrt{{B}^{2} - 4 \times A \times C } }{2 A}$

$- ( - 5)\frac{± \sqrt{{ - 5}^{2} - 4 \times 1 \times 6 } }{2 \times 1}$

$\cancel - ( \cancel - 5) \frac{± \sqrt{{ - 5}^{2} - 4 \times 1 \times 6 } }{2 \times 1}$

$5\frac{± \sqrt{25 - 24 }}{2 }$

$5\frac{± \sqrt{1 }}{2 }$

$\frac{5± \sqrt{1 }}{2 }$

PLUS

$x = \frac{(5 + 1)}{2}$

$x = (\frac{6 }{2} )$

$x = \cancel{ \frac{6}{2} }$

$x = 3$

MINUS

$x = \frac{(5 - 1)}{2}$

$x = ( \frac{4}{2} )$

$x = \cancel{ \frac{4}{2} }$

$x = 2$

Answer 2

Answer:

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