Question

find the zeros of the quadratic polynomial(x2 5x 6) and verify the relation between the zeroes and the coefficients

Answer 1

it is sufficient for your question

Answer 2

Explanation:

We have the quadratic polynomial x²+5x+6

splitting the middle term, we get

= x²+2x+3x+6

= x(x+2)+3(x+2)

= (x+2)(x+3)

So, the values of x²+5x+6 is zero when x+2=0 Or x+3=0

i.e ., when x = -2 Or x = -3

Therefore, the zeroes of x²+5x+6 are -2 and -3

Now ,

Verification:

i)the sum of the Zeroes = -2+(-3)

= -5

= (-5)/1

= $\frac{-(coefficient\:of \:x)}{coefficient\:of\:x^{2}}$

ii) Product of the zeroes

= (-2)(-3)

= 6

= 6/1

=$\frac{(constant\:term)}{coefficient\:of\:x^{2}}$

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