Question

Find the zeros of the quadratic polynomial x²+5x+6 and verify the relation between the zeros and the coefficients

CONTENT QUALITY ANSWER REQUIRED

Answer 1

p(x)=x²+5x+6
x²+3x+2x+6
x(x+3)+2(x+3)
(x+3)(x+2)=0
x+3=0 x+2=0
x=-3 x=-2
alpha=-3 and beta=-2
therefore,
zeros of the quadratic polynomial is -3 and -2.
sum of the zeros=(alpha)+(beta) =-3+(-2)=-3-2=-5=(-coefficient) of x/(coefficient of x²)
product of zeros=(-3)×(-2)=6/1=constant term/(coefficient of x²)

Answer 2

X²+5X+6=0
X²+2X+3X+6=0
X(X+2)+3(X+2)=0
(X+2)(X+3)=0
THEN. X= -3 ,&-2
AND THE COFFIECIENT OF X² IS 1
AN COFFIECIENT OF X IS 5
AND C IS 6
NOW , WE KNOW THE

As you, can see the sum of the roots is indeed −b/a and the product of the roots is c/a.
Y=x²+bx+c
Y=x²+5x+6
Y=(x+3),(x+2)
Sum of roots = =-2+(-3)=-5
Amd and products of roots =-2*(-3)=6
And the formula is - b/a for sum =-5/1=-5
And formula for products =c/a=6/1=6
I hope you understand very well dear, :-)