find the zeros of the quadratic polynomial xsquare+7x+12 and verify the relation between the zeros and it coefficients
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JASHANDEEPcheema:
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✴✴ Hey friends!!✴✴
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✴✴ Here is your answer↓⬇⏬⤵
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
▶⏩ x² + 7x + 12.
→ a = 1; b = 7; c = 12.
=> Factorise this quadratic equation:-)
↪➡ x² + 4x + 3x + 12 = 0.
↪➡ x(x + 4) + 3(x + 4) = 0.
↪➡ (x + 3) ( x + 4)= 0.
=> x + 3 = 0. | x + 4 = 0.
=> x = -3. | x = -4.
=> œ = -3. | ß = -4.
[ œ = alpha , and ß = beta].
▶⏩ Hence, zeros of polynomial are -3 and -4.✔✔
▶⏩ Verification:-)⤵⤵⤵⤵⤵⤵
→ we know that :-)
=> œ + ß = -b/a.
[ Put the value of œ and ß ].
↪➡ -3 + (-4) = -7/1.
↪➡ -3 -4 = -7.
↪➡ -7 = -7.✅✅.
✴✴ Hence, it is verified ✴✴.
✴✴ Thanks!!✴✴.
☺☺☺ Hope it is helpful for you ✌✌✌.
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✴✴ Here is your answer↓⬇⏬⤵
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
▶⏩ x² + 7x + 12.
→ a = 1; b = 7; c = 12.
=> Factorise this quadratic equation:-)
↪➡ x² + 4x + 3x + 12 = 0.
↪➡ x(x + 4) + 3(x + 4) = 0.
↪➡ (x + 3) ( x + 4)= 0.
=> x + 3 = 0. | x + 4 = 0.
=> x = -3. | x = -4.
=> œ = -3. | ß = -4.
[ œ = alpha , and ß = beta].
▶⏩ Hence, zeros of polynomial are -3 and -4.✔✔
▶⏩ Verification:-)⤵⤵⤵⤵⤵⤵
→ we know that :-)
=> œ + ß = -b/a.
[ Put the value of œ and ß ].
↪➡ -3 + (-4) = -7/1.
↪➡ -3 -4 = -7.
↪➡ -7 = -7.✅✅.
✴✴ Hence, it is verified ✴✴.
✴✴ Thanks!!✴✴.
☺☺☺ Hope it is helpful for you ✌✌✌.
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