find the zeros of the qudratic polynomial x^2+7x +10 and verify the relationship between the zeros and it's coefficient
Answers
Step-by-step explanation:
x^2+2x+5x+10
x(x+2) +5(x+2)
(x+5) (x+2)
x+5=0. x+2=0
x= -5. x= -2
This is verified that zeroes and coefficients of quadratic equation are related to each other
Step-by-step explanation:
We are given with a quadratic equation,
and we have to verify the relationship between zeroes and coefficients of equation.
- Formula used,
According to standard quadratic equation,
Sum of zeroes
Product of zeroes
a is the coefficient of , b is for coefficient of and c is the constant.
- Calculation for zeroes
we have,
we can find zeroes by using factorization method,
we can write as and .
Zeroes of quadratic equation are -2, -5.
- Verification of relationship between coefficients and zeroes
We have coefficients of and constant ,
, and .
1). Sum and product of zeroes by using coefficients,
Sum of zeroes Product of zeroes
2). Sum and product of zeroes by using calculated zeroes,
let zeroes of equation α and β,
and .
so the sum of zeroes product of zeroes
Thus we can see sum and product of zeroes by coefficient and by calculated zeroes are same.
So this is verified they are related to each other.