Question

Find the zeros of the
${x}^{2} - 2x - 8$
and verifythe relationshipbetween the zeros and the coefficients
​

Answer 1

Answer:

Hope it helps :)

Step-by-step explanation:

$=x^2+2x-4x-8\\\\\\=x(x+2)-4(x+2)\\\\\\=(x-4)(x+2)~~[required~answer]$

x = 0 + 4 = 4

x = 0 - 2 = -2