Question

find the zeros of which of the following quadratic polynomial and verify the relationship between the zeros and the coefficients 3 x square - 4 x + 1​

Answer 1

Answer:

▶Here's your answer

$3 {x}^{2} - 4x + 1 \\ \\ = 3 {x}^{2} - 3x - x + 1 \\ \\ = 3x(x - 1) - 1(x - 1) \\ \\ = (3x - 1)(x - 1) \\ \\ \alpha = \frac{1}{3} \: and \: \beta = 1$

➡We know that

$\alpha + \beta = \frac{ - b}{a} \\ \\ \frac{1}{3} + 1 = \frac{ + 4}{3} \\ \\ \frac{1 + 3}{3} = \frac{4}{3} \\ \\ \frac{4}{3} = \frac{4}{3}$

➡And

$\alpha \beta = \frac{c}{a} \\ \\ \frac{1}{3} \times 1 = \frac{1}{3} \\ \\ \frac{1}{3} = \frac{1}{3}$

Hence Verified... ❗

Hope it helps ❤❗

Answer 2

HEYA MATE

HOPE IT HELPS