Question

find the zeros of x square - 22x +72 and verify relationship between zeros and coefficients

Plz help me i will chose the brainlist......... ​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

The roots are 18,4

Step-by-step explanation:

x^2-22x+72=0

here root D= root of (22)^2-4*1*72

                  = root of 484-288

                  = root of 196

                  = 14

=> x=a =-(-22)+14/2*1                     or x=b= -(-22)-14/2*1

      = 22+14/2                                 = 22-14/2

      = 36/2                                       = 8/2

      =18                                            = 4

Now to verify the relationship between the roots of this equation:-

a+b= 18+4=22

-B/A = -(-22)/1=22

=> a+b= -B/A

ab= (18) (4)= 72

C/A = 72/1 = 72

=> ab= C/A

Hence, the roots of the given equation are verified.

Hope it helps. :)