Question

Find the zeros of

x²-x-2​

Answer 1

${x^{2}-x-2}$

SUM = -1

PRODUCT = -2

PAIRS = -2 , 1

So,

x² - 2x + x - 2

x ( x - 2) + 1 ( x - 2)

( x + 1)(x - 2)

x = -1 , x = 2

___________________________

The zeroes are $\red{\huge{-1,2}}$

Answer 2

◆◆HEY MATE HERE IS YOUR SOLUTION◆◆◆

◆ X^2 - X - 2

= X^2 - 2X + X - 2

= X( X - 2) +1(X - 2)

= (X - 2) (X + 1)

WHEN

x - 2 = 0

x = 2

when

x +1 = 0

x = -1