Find the zeros of x⁴+5x³-8x²-10x+12,if it's two zeroes are √2 and -√2
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P(x) = x⁴ + 5x³ -8x² -10x +12
now roots = √2 and -√2 ⇒ p(x) is divisible by (x-√2)(x + √2) = x² - 2
P(x) = (x² - 2)(x² +5x - 6) ⇒ (x² - 2)( x² +6x - x - 6 )
⇒ (x²-2)(x+6)(x-1)
so other roots gonna be -6 and 1
hope this would b helpful...........
now roots = √2 and -√2 ⇒ p(x) is divisible by (x-√2)(x + √2) = x² - 2
P(x) = (x² - 2)(x² +5x - 6) ⇒ (x² - 2)( x² +6x - x - 6 )
⇒ (x²-2)(x+6)(x-1)
so other roots gonna be -6 and 1
hope this would b helpful...........
AyushKhurana:
Thank you
can u mark it as brainliest? thank u in advance
I don't know how
its alright well do u have any doubt in this question?
No it was very clear thank you
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