Math, asked by jannesa, 6 months ago

find the zeros of y²-18 and verify the the relation between zeroes and the coefficient​

Answers

Answered by Anonymous
1

y^2 - 18 = 0

y^2 = 18

y = -+√18

y = -3√2 or 3√2

verification

sum of zeroes = -3√2 + 3√2 = 0 = -b/a =

-(coefficient of x ) / (coefficient of x^2)

product of zeroes = -3√2 X 3√2 = - 9 X 2 = -18

= c / a = constant / coefficient of x^2

Answered by Anonymous
1

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