Question

prove that sec theta+tan theta-1/tan theta-sec theta=cos theta/1-sin theta​

Answer 1

tanθ+secθ−1

tanθ+secθ−1

tanθ+secθ−1 =

tanθ+secθ−1 = cosθ

tanθ+secθ−1 = cosθ1+sinθ

tanθ+secθ−1 = cosθ1+sinθ

tanθ+secθ−1 = cosθ1+sinθ

tanθ+secθ−1 = cosθ1+sinθ Solution:

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S =

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan 2

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan 2 θ=1

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan 2 θ=1=

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan 2 θ=1= tanθ−secθ+1

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan 2 θ=1= tanθ−secθ+1tanθ+secθ−(sec

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan 2 θ=1= tanθ−secθ+1tanθ+secθ−(sec 2

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan 2 θ=1= tanθ−secθ+1tanθ+secθ−(sec 2 θ−tan

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan 2 θ=1= tanθ−secθ+1tanθ+secθ−(sec 2 θ−tan 2

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan 2 θ=1= tanθ−secθ+1tanθ+secθ−(sec 2 θ−tan 2 θ)

tanθ+secθ−1 = cosθ1+sinθ Solution:L.H.S = tanθ−secθ+1tanθ+secθ−1 We can write, sec 2 θ−tan 2 θ=1= tanθ−secθ+1tanθ+secθ−(sec 2 θ−tan 2 θ)