Math, asked by subi7059, 6 months ago

find the zeros of yhe polynomial x(x-2)(x-3)​

Answers

Answered by rupatejaswi
2

Answer:

x=1

Step-by-step explanation:

x(x-2)(x-3)

when x gets multiplied to (x-2)

(x²-2x)(x-3)

product of the two terms

x³+3x²-2x²+6x

x³+x²+6x=0

x³+x²+x+6=0

x³+x²+x=6

6x=6

x=6/6

x=1

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