find the zeros of yhe polynomial x(x-2)(x-3)
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Answer:
x=1
Step-by-step explanation:
x(x-2)(x-3)
when x gets multiplied to (x-2)
(x²-2x)(x-3)
product of the two terms
x³+3x²-2x²+6x
x³+x²+6x=0
x³+x²+x+6=0
x³+x²+x=6
6x=6
x=6/6
x=1
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