Question

Find the zeros
$2 {x}^{2} \: + 9 \times 7 = 0$
​

Answer 1

Answer:

Let start

Step-by-step explanation:

Explanation

Notice that 9=2+7

So we find

0=2x^2-9x+7

= 2x^2-2x-7x+7

= 2x( x-1)-7(x-1)

= (2x-7) (x-1)

Hence Zeros x=7/2

And X= 1

thanks dear friend

I hope you help