Question

Find the zeros
$2x^2 - 5x + 3$
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Answer 1

Answer:p(x)=2x2−5x−3p(x)=0⇒2x2−5x−3=0⇒2x2−6x+x−3=0⇒2x(x−3)+1(x−3)=0⇒(2x+1)(x−3)=0x=2−1,3.

Answer 2

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1.Use the sum-product pattern

2x^2−5+3

2x^2−5+322−2−3+3

2.Common factor from the two pairs

2x^2−2−3+3

2x^2−2−3+32(−1)−3(−1)

3.Rewrite in factored form

2x(x−1)−3(x−1)

(2x-3 )(x-1)

4. Solution

(2−3)(x−1)

Ur Answer = (2−3)(x−1)