Math, asked by vibhabisht00pbk5of, 11 months ago

Find the zeros

X²-14X+33

Answers

Answered by ᎷíssGℓαмσƦσυs
1

x²-14x+33=0

x²-11x-3x+33=0

x(x-11)-3(x-11)=0

(x-11)(x-3)

x=11,3

first ....

121-14×11+33

154-154

=0

Answered by Angel1l
0

Answer:

3 and 11

Step-by-step explanation:

For zeros

P(x)=0

x^2 -14x+33=0

x^2-11x-3x+33=0

x(x-11)-3(x-11)=0

(x-11)(x-3)=0

x-11=0 or x-3=0

x=11,3

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