Find the zewo of the polynomial
P(x) =(x-4) ² (16)
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p(x)=x
3
−5x
2
−16x+80
Let α,β,γ are the zeroes of polynomial p(x) such that α+β=0.
Then,
Sum of zeros = −
Coefficient of x
3
Coefficient of x
2
α+β+γ=5
0+γ=5
γ=5
Also,
Product of zeros = −
Coefficient of x
3
Constant term
αβγ=−80
−5α
2
=−80
α
2
=16
α=±4
Now,
α+β=0
⟹±4+β=0
β=∓4
Thus, zeros of the given polynomial are 4,−4,5.
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