find theacceleration due to gravity in a mine depth of 640m if the value at the surface is 9.8m/s.The radius of the earth is 6400km
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The depth, d = 640 m
The radius of the earth, R = 6400 km = 6.4×106 m
The value of acceleration due to gravity at the surface of the earth, g = 9.8 m/s2
Therefore, the acceleration due to gravity at the depth of 640 m
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Answer:
Explanation:
using g at depth=g(1-d/r)
=98/10(1-640/6400)
=98/10(5760/6400)
=98/10*9/10
after simplifying
=8.82m/s²
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