Math, asked by kittania845, 9 months ago

find thefind the least number divisible by all natural number from 5 to 15 both inclusive

Answers

Answered by shanukumar16372
6

Answer:

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Answered by soniatiwari214
2

Concept

First we will write all the natural numbers between 5 to 15 including 5 and 15 too. Then we will calculate the LCM of these numbers. Since the LCM will be the product of the factors, therefore the LCM will be the number which is divisible by all the natural numbers from 5 to 15.

Given

The given natural numbers are 5, 6, 7, 8, 9,10,11, 12, 13, 14, 15.

Find

We have to calculate the least number which is divisible by all the natural numbers from 5 to 15.

Solution

5=1*5

6=1*2*3

7=1*7

8=1*2*2*2

9=1*3*3

10=1*2*5

11=1*11

12=1*2*2*3

13=1*13

14=1*2*7

15=1*3*5

Therefore , the LCM will be,

LCM=1*2*2*2*3*3*7*5*11*13

Which is equal to, LCM=360360

Hence the least value which is divisible by all the natural numbers from 5 to 15 is 360360.

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