find thefind the least number divisible by all natural number from 5 to 15 both inclusive
Answers
Answer:
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Concept
First we will write all the natural numbers between 5 to 15 including 5 and 15 too. Then we will calculate the LCM of these numbers. Since the LCM will be the product of the factors, therefore the LCM will be the number which is divisible by all the natural numbers from 5 to 15.
Given
The given natural numbers are 5, 6, 7, 8, 9,10,11, 12, 13, 14, 15.
Find
We have to calculate the least number which is divisible by all the natural numbers from 5 to 15.
Solution
5=1*5
6=1*2*3
7=1*7
8=1*2*2*2
9=1*3*3
10=1*2*5
11=1*11
12=1*2*2*3
13=1*13
14=1*2*7
15=1*3*5
Therefore , the LCM will be,
LCM=1*2*2*2*3*3*7*5*11*13
Which is equal to, LCM=360360
Hence the least value which is divisible by all the natural numbers from 5 to 15 is 360360.
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