Question

find ther zeroes of the quadratic polynomial 2ײ+2×-12 and verify the relationship between the zeroes and the coefficients​

Answer 1

Answer:

it's one zero is 2

and second is -3

Answer 2

Answer:

$2x ^{2} + 2x - 12 \\ = 2x^{2} + 6x - 4x - 12 \\ = 2x(x + 3) - 4(x + 3) \\ = (2x - 4)(x + 3)$

equating (2x - 4) and (x + 3), we get

$(2x - 4) = 0 \\ => 2x = 4 \\ = > x = \frac{4}{2} \\ = > x = 2$

$(x + 3) = 0 \\ = > x = - 3$

now , we get two zeroes 2 and -3.

sum of the zeroes ,

$- 3 + 2 = \frac{ - 1}{1} = \frac{ - 2}{2} = \frac{ - coefficient \: of \: x}{coeffiient \: of {x}^{2} }$

product of the zeroes,

$- 3 \times 2 = \frac{ - 6}{1} = \frac{ - 12}{2} = \frac{constnt \: term}{coefficient \: of \: {x}^{2} }$

Hope it helps you mate__________