Find theratio area of the square formed on the diagonal of rectangle to the atea reactangle whose lenghtg is twice the bredtg
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Breadth of rectangle = b
Given length of rectangle = 2xb
So Area of rectangle = 2 x b^2
Diagonal of rectangle = Root of (b^2 + (2b)^2) = root of (5 b^2) = b x root 5
Therefore side of Square = b x root 5
Area of square = (b x root 5) X( b x root 5) = 5 x b^2
Area of square : Area of rectangle = 5xb^2 : 2xb^2 = 5:2
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