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a.Length of AB is 10cm and PB is 4cm
Therefore
AB =PA +PB
10=PA+4
PA=10-4
PA=5cm
b. Length of DC is also 10 because DC and AB are also diameters of the circle.
Therefore,
PC+PD=DC
3+PD=10
PD=10-3
PD=7cm
Q16. a. QOB+AOQ= 180 (linear pair)
50+AOQ=180
AOQ=180-50
AOQ=130
b.
Therefore
AB =PA +PB
10=PA+4
PA=10-4
PA=5cm
b. Length of DC is also 10 because DC and AB are also diameters of the circle.
Therefore,
PC+PD=DC
3+PD=10
PD=10-3
PD=7cm
Q16. a. QOB+AOQ= 180 (linear pair)
50+AOQ=180
AOQ=180-50
AOQ=130
b.
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