Find
thesum
of all odd positive
integers
lers
te
450.
Answers
Answered by
1
Step-by-step explanation:
Odd positive integers= 1, 3, 5, 7,..., 445, 447, 449.
This forms an AP with
first term, a = 1
last term, l = 449
common difference, d = 2
Now, l = a + (n-1)×d
449 = 1 + (n-1)(2)
449 = 1 + 2n - 2
2n = 450
n = 225
Sum of AP = n/2 × (a+l)
= 225/2 × (1 + 449)
= 225/2 × 450
= 225 × 225
= 50624
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