Math, asked by jayakhurana1970, 8 months ago

find thevalue of k for kx²-2√5+4=0 so that it has two equsl roots

Answers

Answered by shrutis1812593

1

Answer:

D=b^2-4ab

0=(2root5)^2-4k×4

0=4×5-16k

0=20-16k

16k=20

k=20/16

k=5/4

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