Question

Find this answers please​

Answer 1

PBP

-----------

HHB

where sin theta = P/H

cos theta = B/H

tan theta = P/B

(11)

sin theta = 5/13 = P/H

P = 5, H = 13

H²= P²+B²

B²= H² -P² = 13²-5² = 144

B=12

P=5,B=12, H= 13

cos theta = B/H = 12/13

tan theta = P/B = 5/12

(5sin theta -2cos theta)/tan theta

=( 5×5/13 - 2×12/13)/ 5/12

= (25/13 - 24/13)/ 5/12

=( 1/13)/ (5/12)

1/13 × 12/5

= 12/65

10 is same as 11th

there cot theta = 1/tan theta = B/P

cosec theta = 1/sin theta = H/P