find this solution. of three ques also
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Sum of interior angle of a polygon=(n-2)180°
Where n=no. Of sides
(I) 1800=(n-2)180
1800/180=n-2
10=n-2
10+2=n
NO.of side=12
2)1440=(n-2)180
1440/180=n-2
8=n-2
8+2=n
n=10
3)18*90=1620 =(n-2)180
1620/180=n-2
9=n-2
9+2=n
n=11
Where n=no. Of sides
(I) 1800=(n-2)180
1800/180=n-2
10=n-2
10+2=n
NO.of side=12
2)1440=(n-2)180
1440/180=n-2
8=n-2
8+2=n
n=10
3)18*90=1620 =(n-2)180
1620/180=n-2
9=n-2
9+2=n
n=11
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