find thr midterm of (x/3+2/y) 6
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Answered by
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the answer is 20(x/3)³(2/y)³.= 20(x³/27)(8/y³)
=(160x³)/(27y³)
Hope it helps u :-)
=(160x³)/(27y³)
Hope it helps u :-)
lekhahasa:
please mark it as brainliest
where is the explanation
Answered by
1
Number of terms in the expasion = 6+1=7
Middle term = (n+1)/2
= (7+1)/2=4
General term in the expansion of the binomial (x+a)^n is
T r+1 = ncr* x^(n-r) * a^r
Here
r=3, n=6
T 4= T (3+1)
= 6c4 * (x/3)^(6-3)* (2/y)^3
=6!/[(6-3)!3! * (x/3)^3 *(2/y)^3
=160/27 * (x/y)^3
Middle term = (n+1)/2
= (7+1)/2=4
General term in the expansion of the binomial (x+a)^n is
T r+1 = ncr* x^(n-r) * a^r
Here
r=3, n=6
T 4= T (3+1)
= 6c4 * (x/3)^(6-3)* (2/y)^3
=6!/[(6-3)!3! * (x/3)^3 *(2/y)^3
=160/27 * (x/y)^3
:)
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