Find three consective odd number whose sum is 147
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heyaa.....your answer is here
let 1st no =x
2nd no=x+2
3rd no =x+4
at
sum of these 3 number =147
x+x+2+x+4=147
3x+6=147
3x=147-6
3x=141
x=141/3
x=47
hence 1st no=x=47
2nd no =x+2=47+2=49
3rd no =x+4=47+4=51
HOPE IT HELPS YOU MARK AS BRAINLIEST PLS....
let 1st no =x
2nd no=x+2
3rd no =x+4
at
sum of these 3 number =147
x+x+2+x+4=147
3x+6=147
3x=147-6
3x=141
x=141/3
x=47
hence 1st no=x=47
2nd no =x+2=47+2=49
3rd no =x+4=47+4=51
HOPE IT HELPS YOU MARK AS BRAINLIEST PLS....
Anonymous:
Is 48 odd integer.Its not I guess.
Let the odd positive consecutive integer be 'X+1','X+3' and 'X+5'. X+1+X+3+X+5=147. 3X+9=147. X=46 So X+1=47. X+3=49.X+5=51.You should solve it like this.
Answered by
0
Let the odd positive consecutive integer be 'X+1','X+3' and 'X+5'. So, X+1+X+3+X+5=147. 3X+9=147. X=46 So X+1=47. X+3=49.
X +5=51. I hope it helps.
X +5=51. I hope it helps.
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