Question

find three consecurive numbers such that if they are divided by 10,17,and 26 respectivly,the sum of their quotient will be 10

Answer 1

Hi ,

Let x , ( x + 1 ) , ( x + 2 ) are three consecutive

numbers ,

according to the problem given,

x / 10 + ( x + 1 ) / 17 + ( x + 2 ) / 26 = 10

LCM ( 10 , 17 , 26 ) = 2210

{ [ 221x + 130(x+ 1 ) + 85 ( x + 2 ) ] / 2210 } = 10

221x + 130x + 130 + 85x + 170 = 22100


436x + 300 = 22100

436 x = 22100 - 300

436 x = 21800

x = 21800 / 436

x = 50

Therefore ,

Required three consecutive numbers are ,

x , ( x + 1 ) , ( x + 2 )

50, 51 , 52

I hope this helps you.

:)