find three consecutive even natural numbers whose sum is 87
Answers
Answered by
17
Let the number be x, x + 2 and x + 4
According to the question,
x + x + 2 + x + 4 = 87
3x + 6 = 87
3x = 87 - 6
3x = 81
x =
x = 27
1st number = 27
2nd number = x + 2 = 27 + 2 = 29
3rd number = x + 4 = 27 + 4 = 31
According to the question,
x + x + 2 + x + 4 = 87
3x + 6 = 87
3x = 87 - 6
3x = 81
x =
x = 27
1st number = 27
2nd number = x + 2 = 27 + 2 = 29
3rd number = x + 4 = 27 + 4 = 31
Answered by
11
❤❤Here is your answer ✌ ✌
Let,
The number be x, x + 2 and x + 4
A/q
➡x + x + 2 + x + 4 = 87
➡3x + 6 = 87
➡3x = 87 - 6
➡3x = 81
x = 81/3
x = 27
➡1st number = X=27↩
➡2nd number = x + 2 = 27 + 2 = 29↩
➡3rd number = x + 4 = 27 + 4 = 31↩
Let,
The number be x, x + 2 and x + 4
A/q
➡x + x + 2 + x + 4 = 87
➡3x + 6 = 87
➡3x = 87 - 6
➡3x = 81
x = 81/3
x = 27
➡1st number = X=27↩
➡2nd number = x + 2 = 27 + 2 = 29↩
➡3rd number = x + 4 = 27 + 4 = 31↩
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