find three consecutive even number whose sum is 234
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Answered by
3
let the three numbers be x,x+2 and x+4
so x+x+2+x+4=234
3x+6=234
3x=228
x=228/3=76
so the three numbers are 76,78 ,nd 80
so x+x+2+x+4=234
3x+6=234
3x=228
x=228/3=76
so the three numbers are 76,78 ,nd 80
Answered by
2
given sum of three consecutive integer = 234
234 = 2 × 3 × 3 × 13
= 2 × ( 3 × 3 ) × 13
take one 3 out from the pair.
2 × 3 × 13 = 78
subtract 2 or add 2 in the obtained number for getting other two numbers.
first number = 78 - 2 = 76
second number = 78 ( itself )
third number will be = 78+ 2 = 80
76 + 78 + 80 = 234
hence, the required three consecutive even numbers are 76 , 78 , 80 .
234 = 2 × 3 × 3 × 13
= 2 × ( 3 × 3 ) × 13
take one 3 out from the pair.
2 × 3 × 13 = 78
subtract 2 or add 2 in the obtained number for getting other two numbers.
first number = 78 - 2 = 76
second number = 78 ( itself )
third number will be = 78+ 2 = 80
76 + 78 + 80 = 234
hence, the required three consecutive even numbers are 76 , 78 , 80 .
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