find three consecutive even numbers such that the sum of first and third is 40
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let the numbers be x,x+2,x+4
x+x+4=40
2x+4=40
2x=40-4
2x=36
x=36/2
x=18
first number =x=18
second number=x+2=18+2=20
third number=x+4=18+4=22
let the numbers be x,x+2,x+4
x+x+4=40
2x+4=40
2x=40-4
2x=36
x=36/2
x=18
first number =x=18
second number=x+2=18+2=20
third number=x+4=18+4=22
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