Question

find three consecutive even numbers such that the sum of the first and the last numbers exceed s the middle number by 20 .

Answer 1

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HERE'S THE ANSWER...

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♠️ Let those numbers be

⏺️ ( x - 2 ) , ( x ) and ( x + 2 )

▶️Sum of the first and the last numbers exceed s the middle number by 20 .

=> ( x - 2 ) + ( x + 2 ) = x + 20

=> x - 2 + x + 2 = x + 20

=> 2 x = x + 20

=> 2 x - x = 20

=> [ x = 20 ]✔️✔️

♠️ So the numbers are

⏺️ First no. = x - 2

=> 20 - 2

=> 18 ✔️

⏺️ Middle no. = x

=> 20 ✔️

⏺️ Last no = x + 2

=> 20 + 2

=> 22 ✔️


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Answer 2

no are x , x + 2 , x + 4

ATQ

x + x + 4 = x + 2 + 20

2x + 4 = x + 22

2x - x = 18

x = 18

Number are

x , x + 2 , 2x + 2

18 , 20 and 22

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