Question

Find three consecutive even numbers whose sum is 96. 6. The length of a rectangle exceeds twice its width by 3.Find the length and width of the rectangle if its perimeter is 246m.

Answer 1

Answer:

Let breadth be equal to x

then length= 2x+3

perimeter of rectangle= 2(l+b)

= 4x +6 +2x  

=6x +6  

we know the perimeter

so it would be  

246=6x+6

240=6x

x = 240/6

x=40m

Breadth = 40m

Length = 80+3=83m

Step-by-step explanation:

mark as brainliest

Answer 2

Given:

• Sum of three consecutive even numbers is 96.

To Find:

• What are the numbers ?

Solution: Let the first even number be x. Therefore,

➙ Second number = (x + 2)

➙ Third number = (x + 4)

A/q

• First + second + third = 96

$\implies{\rm }$ x + x + 2 + x + 4 = 96

$\implies{\rm }$ 3x = 96 – 6

$\implies{\rm }$ x = 90/3

$\implies{\rm }$ x = 30

So,

➙ First even no. is x = 30

➙ Second is x + 2 = 30 + 2 = 32

➙ Third is x + 4 = 30 + 4 = 34

_______________________

Given:

• Length of rectangle exceeds twice width by 3 m.
• Perimeter of rectangle is 246 m.

To Find:

• What are the length and width of rectangle ?

Solution: Let the width of rectangle be z m. Therefore,

➟ Length = 2 times of z + 3

➟ length = (2z + 3)

As we know that

★ Perimeter of Rect. = 2(Length + Width) ★

A/q

• Perimeter is 246 m.

$\implies{\rm }$ 246 = 2(2z + 3 + z)

$\implies{\rm }$ 246 = 2(3z + 3)

$\implies{\rm }$ 246 = 6z + 6

$\implies{\rm }$ 246 – 6 = 6z

$\implies{\rm }$ 240/6 = z

$\implies{\rm }$ 40 = z

So, measure of

➬ Width of rectangle is z = 40 m

➬ Length is 2(40) + 3 = 80 + 3 = 83 m

________(◔‿◔)_______