find three consecutive integers such that the smallest integer plus one fifth of the next minus half of the largest integer gives nine .
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X, X+1, X+2
X+1/5(X+1)-1/2(X+2) = 9
X + X/5 + 1/5 - X/2 - 1 = 9
(10X + 2X - 5X)/10= 9+1-1/5
7X/10 = 50-1/5
7X/10 = 49/5
X = 49/5*10/7
X = 7*2 = 14
14,15,16
X+1/5(X+1)-1/2(X+2) = 9
X + X/5 + 1/5 - X/2 - 1 = 9
(10X + 2X - 5X)/10= 9+1-1/5
7X/10 = 50-1/5
7X/10 = 49/5
X = 49/5*10/7
X = 7*2 = 14
14,15,16
Anonymous:
Good!!!
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