Question

find three consecutive integers such that the sum of the first twice the second and 30 times the third is-76​

Answer 1

Step-by-step explanation:

Let the 3 consecutive values be x, x+1, x+2

x + 2(x+1) + 30(x+2) = -76

x + 2x + 2 + 30x + 60 = -76

33x + 62 = -76

33x = -76-62

x = -138/33