Question

find three consecutive multiples of 3 whose sum is 71​

Answer 1

Hey there!

Here's your answer:

Let the three consecutive multiples of 3 be x , x+3 and x+6.

Given, the sum of x, x+3 and x+6 is 71.

• x + x+3 + x+6 = 71
• 3x + 9 = 71
• 3x = 71 - 9
• 3x = 62
• x = 62/3
• x = 2.66

Therefore x = 2.66 , x + 3 = 5.66 and x +6 = 8.66.

Hope helped!~~

Answer 2

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