find three consecutive natural no.such that the sum of the first and second no. is 15 more than the third .
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Step-by-step explanation:
let x +x=15-x
transpose-xto lhs
x+x+x=15
3x=15
x=15÷3
=5
15-5
first no=10
second no =5
third no 15-10+5
=10
Answered by
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Answer:
It's is correct Tirth Patel
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