Math, asked by geetsharma2552, 10 months ago

find three consecutive natural no.such that the sum of the first and second no. is 15 more than the third .​

Answers

Answered by tirthpatel7
0

Step-by-step explanation:

let x +x=15-x

transpose-xto lhs

x+x+x=15

3x=15

x=15÷3

=5

15-5

first no=10

second no =5

third no 15-10+5

=10

Answered by vaishu03tarun
0

Answer:

It's is correct Tirth Patel

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