In a AABC, 2B> C. If AM is the bisector of ZBAC and AN IBC, then
ZMAN
1) (ZB - 2C) 2) (ZB - 2C)
3) (ZB-ZC
4) 1 / 1 LB + LC)
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Answer:
mark me brainliest and then maybe I will solve
Step-by-step explanation:
do we have a deal ?hmm
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