Question

Find three consecutive natural numbers such that the sum of the first and the third is 13 more than the second. *

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Answer 1

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

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$\large{\green{\underline \bold{\tt{Given :-}}}}$

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• Three consecutive natural numbers

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• Sum of the first and the third is 13 more than the second

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$\large{\red{\underline \bold{\tt{To \: Find :-}}}}$

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• The three consecutive natural numbers

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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• Let the 1st number be x

• Then the 2nd word be x + 1

• So the 3rd word will be x + 2

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$\purple{\underline \bold{According \: to \: the \ question :}}$

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Sum of the first and the third is 13 more than the second

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➜ 2x + 2 = x + 1 + 13

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➜ 2x + 2 = x + 14

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➜ 2x - x = 14 - 2

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➨ x = 12 ------- (1)

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• Hence the 1st number is 12

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$\underline{\bold{\texttt{2nd number :}}}$

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➠ x + 1 ------- (2)

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⟮ Putting x = 12 from (1) to (2) ⟯

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➜ x + 1

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➜ 12 + 1

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➨ 13

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• Hence the 2nd number is 13

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$\underline{\bold{\texttt{3rd number :}}}$

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➠ x + 2 ------ (3)

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⟮ Putting x = 12 from (1) to (3) ⟯

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➜ x + 2

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➜ 12 + 2

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➨ 14

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• Hence the 3rd number is 14

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∴ The consecutive natural numbers are 12 , 13 , 14

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Answer 2

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

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Let the 1st number be x

Then the 2nd word be x + 1

So the 3rd word will be x + 2

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$\purple{\underline \bold{According \: to \: the \ question :}}$

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Sum of the first and the third is 13 more than the second

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➜ 2x + 2 = x + 1 + 13

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➜ 2x + 2 = x + 14

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➜ 2x - x = 14 - 2

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➨ x = 12 ------- (1)

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Hence the 1st number is 12

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$\underline{\bold{\texttt{2nd number :}}}$

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➠ x + 1 ------- (2)

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⟮ Putting x = 12 from (1) to (2) ⟯

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➜ x + 1

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➜ 12 + 1

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➨ 13

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Hence the 2nd number is 13

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$\underline{\bold{\texttt{3rd number :}}}$

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➠ x + 2 ------ (3)

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⟮ Putting x = 12 from (1) to (3) ⟯

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➜ x + 2

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➜ 12 + 2

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➨ 14

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Hence the 3rd number is 14

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∴ The consecutive natural numbers are 12 , 13 , 14

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