Question

Find three consecutive natural numbers such that the sum of the first and second is 15 more than the third

Answer 1

Heya...!

Question solving approach :- We know, every consecutive number differ by 1.just use this approach.Nextly comes,summation. If your father is 15 years greater than you,then his age will be your age + 15.Isn't it ?

In reality,every question is related to daily life.Use it for convenience. You will get desired result.

next,coming to your question

Let the three number be a, a+1, a+2.

now,

A/Q,

a + a + 1 = 15 + a + 2.

=> 2a + 1 = 17 + a

=> a = 16.

thus, three consecutive numbers are 16,17,18 ans.

Regards

KSHITIJ

Answer 2

Solutions :-

Let
The first number be x
second number be x+1
Third number be x+2

sum of the first and second is 15 more than the third

A/q

=>x + (x +1) = (x+2)+15
=>2x + 1 = x + 17
=>2x - x = 17 - 1
=>x = 16

Hence

Thd three consecutive natural numbers are :-

x = 16✔
x + 1 = 16 + 1 = 17✔
x + 2 = 16 + 2 = 18✔

@Anushka