find three consecutive natural numbers whose sum is 33
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3
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Step-by-step explanation:
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Answered by
4
Step-by-step explanation:
let consecutive natural no b x , (x +1 ) ( x +2)
total sum of them = 33
x + x +1 +x +2 = 33
3x +3 =33
3x = 33 -3
3x =30
x = 30/3
x = 10
first num= 10
2nd = x +1 =10+1 =11
3rd = x +2 =10+2 =12
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