find three consecutive number is 3 times the middle number is greater than the sum of the first and the last number by 176
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✿ Solution ✿
Let's assume the consecutive numbers as
x, (x + 1) & (x + 2)
According to Question,
3(x + 1) - 176 = x + (x + 2)
⇒ 3x + 3 - 176 = 2x + 2
⇒ 3x - 173 = 2x + 2
⇒ 3x - 2x = 2 + 173
⇒ x = 175
❁ Required Numbers ❁
✦ x = 175
✦ x + 1 = 175 + 1 = 176
✦ x + 2 = 175 + 2 = 177
Hence, the consecutive numbers are 175, 176 & 177
✪ Be Brainly ✪
Let's assume the consecutive numbers as
x, (x + 1) & (x + 2)
According to Question,
3(x + 1) - 176 = x + (x + 2)
⇒ 3x + 3 - 176 = 2x + 2
⇒ 3x - 173 = 2x + 2
⇒ 3x - 2x = 2 + 173
⇒ x = 175
❁ Required Numbers ❁
✦ x = 175
✦ x + 1 = 175 + 1 = 176
✦ x + 2 = 175 + 2 = 177
Hence, the consecutive numbers are 175, 176 & 177
✪ Be Brainly ✪
Answered by
1
let the three consecutive numbers be x ;x + 1 ,X + 2
according to the question ;
3 ( X + 1 )- (X + X + 2) is equal to 176
3x+3-(2x +2)=176
3 X + 3 -2x -2= 176
X+1=176
X=175
X+1=176
X+2=177
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