find three. consecutive number such tha 7 times the smallest number is equal to 3 times of sum of other 2
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Let the three numbers be x, x+1, x+2
then,
7x = 3(x+1+x+2)
7x = 6x+9
x = 9
x+1 = 10
x+2 = 11
therefore the three consecutive numbers are 9,10 and 11
then,
7x = 3(x+1+x+2)
7x = 6x+9
x = 9
x+1 = 10
x+2 = 11
therefore the three consecutive numbers are 9,10 and 11
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