Math, asked by rajx152, 10 months ago

Find three consecutive number such that 6times the smallest number is equal to double the sum of two.

Answers

Answered by ItzAditt007
3

AnswEr:-

Your Answer Is 3, 4 And 5.

ExplanaTion:-

Given:-

  • Three consecutive integers.

  • 6 times the smallest nber is equal to double the sum of two.

To Find:-

  • The integers.

So ,

Let the smallest integer be x.

So the other two consecutive integers will be (x+1) and (x+2).

Therefore, ATQ:-

Six times the smallest number is double the sum of two.

=》 6x = 2 [(x+1) + (x+2)].

=》 6x = 2 [x + 1 + x + 2].

=》 6x = 2 [2x + 3].

=》 6x = (2 × 2x) + (2 × 3).

=》 6x = 4x + 6.

=》 6x - 4x = 6.

=》 2x = 6.

=》 x = 6/2.

=》 x = 3.

Therefore the smallest integer is x = 3.

So other two consecutive integers are:-

= x + 1.

= 3 + 1.

= 4.

And,

= x + 2.

= 3 + 2.

= 5.

Therefore the three consecutive integers are 3, 4 and 5.

Similar questions