Find three consecutive number such that 6times the smallest number is equal to double the sum of two.
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AnswEr:-
Your Answer Is 3, 4 And 5.
ExplanaTion:-
Given:-
- Three consecutive integers.
- 6 times the smallest nber is equal to double the sum of two.
To Find:-
- The integers.
So ,
Let the smallest integer be x.
So the other two consecutive integers will be (x+1) and (x+2).
Therefore, ATQ:-
Six times the smallest number is double the sum of two.
=》 6x = 2 [(x+1) + (x+2)].
=》 6x = 2 [x + 1 + x + 2].
=》 6x = 2 [2x + 3].
=》 6x = (2 × 2x) + (2 × 3).
=》 6x = 4x + 6.
=》 6x - 4x = 6.
=》 2x = 6.
=》 x = 6/2.
=》 x = 3.
Therefore the smallest integer is x = 3.
So other two consecutive integers are:-
=》 x + 1.
= 3 + 1.
= 4.
And,
=》 x + 2.
= 3 + 2.
= 5.
Therefore the three consecutive integers are 3, 4 and 5.
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